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210 = 2 3 5 7 and the denominator becomes 390 = 1 2 3 5 13 Next, we use these products to build a fraction in which both the numerator and the denominator consist of prime factors, and the denominator has the extra factor 1: (2 3 5 7) / ( 1 2 3 5 13) The common prime factors are 2, 3, and 5 We remove these from both the numerator and the denominator, getting 7/( 1 13) That s 7/( 13) We finish up by multiplying both the numerator and the denominator by 1 to obtain 7/13 This is the lowest form You can check to see that 7/13 = 210/( 390) by dividing 210 by 7 and 390 by 13 You ll get the same integer, 30, in either case

CHAPTER 4 STOCHASTIC PROCESSES drms 14 10 05 12 06 2drms 28 20 10 24 12 CEP 12 08 04 10 05 R95 24 17 09 21 10

When we set out to get rid of the variable z, we decided to work on the first two equations in the revised three-by-three system, and then work on the second two equations You might ask, Why can t we eliminate z between the first equation and the second one, and then between the first equation and the third

Table 42: Summary of conversion factors from the statistic listed in the in the leftmost column to the statistic indicated in the top row, assuming a circular error distribution (ie, = I)

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a Collector lead and and an Emitter lead Referring to the schematic you will note that the vertical line on the transistor symbol is the Base lead, while the Collector lead is connected to the junction of R1 and R2 The Emitter lead has the small arrow pointing downwards which connects to the junction of C2 and R4 Refer to the actual transistor pin-out diagram to see where each lead exits the transistor case Generally small plastic TO-92 transistor case bodies will have all three leads in-a-row with the Emitter at one end, the Base lead in the center, and the Collector lead at the opposite end of the device The induction loop receiver has one integrated circuit at U1, this is an LM386 audio amplifier chip, which has eight leads in a dual in-line package Prior to installing the IC, you should install a good quality IC socket An IC socket is good insurance in the event of a possible circuit failure at some point in time Since most people cannot successfully un-solder an integrated circuit without damaging the PC board, an IC socket makes good sense Place the IC socket on the circuit board and solder it in place on the PC board Locate the LM386 and take a look at the chip You will note that the IC package will have either a cut-out, a notch or small indented circle at one end of the IC package Pin 1 of the IC will be just to the left of the notch or cut-out

one Or between the first and the third, and then between the second and the third The answer is, We can! Either of those alternative schemes will work just as well as the one we chose The intermediate equations will differ, but the ultimate solution to the three-by-three system will turn out the same Whenever you want to solve a three-by-three system of equations, you must somehow involve all three of the equations in the solution process As you continue to study algebra and take more advanced courses, you ll learn other ways to solve three-by-three systems than the methods presented in this book You might also learn techniques to solve four-by-four or larger systems In any case, if you want to find the solution to a system of equations, you must give every one of those equations some say in the outcome

To use this table, nd the row corresponding to the given statistic Multiply this row by the numeric value of that statistic to obtain all the other statistics as indicated in the (top) header row For example, if the R95 statistic is 10 m, them the other statistics are = 04m, drms = 06m, 2drms = 12m, and RCEP = 05m

Here s a challenge!

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