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2 2 The initial conditions are x1 (0) N (0, B0 ) and x2 (0) N (0, R0 ) The stochastic process noise (t) and measurement noise are independent, white, and Gaussian with R ( ) = N 2 ( ) and R ( ) = K 2 ( ) The nomenclature and units related to the various symbols are shown in Table 43

Table 15-2

Eliminate x , solve for y Let s multiply the first equation through by 11 and the second equation through by 10 When we do that, we get

110x 187y = 88 and 110x + 410y = 70 Now let s add these two equations in their entirety: 110x 187y = 88 110x + 410y = 70 223y = 18 Dividing through by 223 tells us that y = 18/223 This fraction happens to be in lowest terms (a fact that you can verify if you like)

Interpretation Random bias, bias, xed drift Rate random walk Angular random walk Rate ramp, Random ramp

Eliminate y , solve for x Let s multiply the first equation in our two-by-two system through by 41 and the second equation through by 17 That gives us

SY (j )

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This table provides the value of alphanumeric coded ceramic, mylar and mica capacitors in general They come in many sizes, shapes, values and ratings; many different manufacturers worldwide produce them and not all play by the same rules Some capacitors actually have the numeric values stamped on them; however, many are color coded and some have alphanumeric codes The capacitor s first and second significant number IDs are the first and second values, followed by the multiplier number code, followed by the percentage tolerance letter code Usually the first two digits of the code represent the significant part of the value, while the third digit, called the multiplier, corresponds to the number of zeros to be added to the first two digits

When you try to factor the numerator and denominator of a fraction into products of primes, you might find that one or the other is already prime or is the negative of a prime Maybe both are like that! This means the original fraction is in lowest form, except when the denominator is negative If the denominator is negative, you simply change both the numerator and the denominator to their additive inverses

K2 2

Here s a challenge!

1st Significant Figure 2nd Significant Figure Multiplier Tolerance 01 F 10% CSGNetworkCom 6/4/92

Suppose that a, b, c, d, e, and f are all primes, and no two of them are the same Reduce the following ratio to its lowest form: ab 3cde /( ab 2ce 3f ) An exponent of 2 after any factor means that the factor appears twice An exponent of 3 after any factor means that the factor appears three times So, for example, b 2 means bb, and b 3 means bbb

N2

This problem is messy but not difficult Let s expand the numerator and the denominator out so we don t have any exponents, and let s put small elevated dots (they can represent multiplication, remember!) between the factors to make them easy to tell apart Let s write the numerator out in full, scratch a long dashed line underneath it, and then below that, write the denominator out in full We get 1 a b b b c d e ----------------------------------------- 1 a b b c e e e f Now it s easy to see which factors are duplicated in the numerator and the denominator They are 1, a, b (twice), c, and e When we remove these factors from the expressions above and below the dashed line, we get b d -----------------------------------------e e f This can be written as bd /e 2f The parentheses in the denominator are no longer needed because the minus sign is gone This ratio is in lowest form because both the numerator and the denominator are products of primes, and none of the primes in the numerator and denominator are duplicates

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